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bosskm2000
@bosskm2000
July 2022
1
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Укажите первообразную функции f(x)=2-sin x.
1)F(x)=2x-cos x
2)F(x)=x²+cos x
3)F(x)=2x + cos x
4)F(x)=2+cos x
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Lesben
F(x)=2-sinx
∫(2-sinx)dx=∫2dx-∫sinxdx=2x-(-cosx)=2x+cosx
Otvet: 3)
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Answers & Comments
∫(2-sinx)dx=∫2dx-∫sinxdx=2x-(-cosx)=2x+cosx
Otvet: 3)