умоляю помогите очень срочно . Created by yanekakashka. algebra-ru

умоляю помогите очень срочно ...

Universalka

Verified answer

$\displaystyle\bf\\\sqrt{(t-7)(t+2)} \\\\(t-7)(t+2)\geq 0$

+ + + + + [- 2] - - - - - [7] + + + + +

///////////////// ////////////////

$\displaystyle\bf\\t\leq -2 \ ; \ t\geq7$

1 votes Thanks 1

yanekakashka спасибо большое

Universalka Пожалуйста

NNNLLL54

Verified answer

Ответ: №3 .

$\sqrt{(t-7)(t+2)}\\\\ODZ:\ \ (t-7)(t+2)\geq 0\ \ ,\ \ \ t_1=7\ ,\ t_2=-2\\\\znaki:\ \ +++[-2\, ]---[\ 7\ ]+++\\\\\\\boxed{\ t\in (-\infty ;-2\ ]\cup [\ 7\ ;+\infty \, )\ }\\\\\\ili:\ \ \ t\leq -2\ ,\ t\geq 7$

1 votes Thanks 0

Answers & Comments

Verified answer

Verified answer

pomogite pozhalujsta 100 ballov dayuf102a5f9670548d52dded183a3a5defd 74312

pomogite pozhalujsta 100 ballov dayud23f7cac84cd4a392704e904bf56d161 99045

oooochen srochno s obyasneniem

рекомендуемые вопросы

Helpful Links

Helpful Social