Ответ:
1.
а) 3х^4-48=3(х^4-16) =3(х+2) (х-2) (х-2) (х-2)
б) (7а^2-2) (7а^2+2) =?
2.
1) 6а+(4а-3) ^2=6а+4а^2-24а+9=4а^2-18а+9
2)(а-0,3) (а^2+0,3а+0,09) =а^3-0,027
3) (3х+4) ^2-(3х-1) (3х+1) =24х+17
4) (3х-2) (2+3х) -(1+х) (х-1) =8х^2-3
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Answers & Comments
Ответ:
1.
а) 3х^4-48=3(х^4-16) =3(х+2) (х-2) (х-2) (х-2)
б) (7а^2-2) (7а^2+2) =?
2.
1) 6а+(4а-3) ^2=6а+4а^2-24а+9=4а^2-18а+9
2)(а-0,3) (а^2+0,3а+0,09) =а^3-0,027
3) (3х+4) ^2-(3х-1) (3х+1) =24х+17
4) (3х-2) (2+3х) -(1+х) (х-1) =8х^2-3