9+(4а-3)(4а+3)-2а(8а-5)=9+(16а²-9)-16а²+10а=9+16а²-9-16а²+10а=10а
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9+(4а-3)(4а+3)-2а(8а-5)=9+(16а²-9)-16а²+10а=9+16а²-9-16а²+10а=10а
Ответ:10а