Упростить данное выражение:. Created by marataglyamov. algebra-ru

Упростить данное выражение:...

marataglyamov @marataglyamov

July 2022 1 17 Report

Упростить данное выражение:

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Lesben

Verified answer

(tg²α-sin²α).(1/sin²α -1)=(sin²α/cos²α -sin²α).((1-sin²α)/sin²α)=
=(sin²α-sin²αcos²α)/cos²α . cos²α/sin²α=sin²α(1-cos²α) . 1/sin²α=
=1-cos²α=sin²α
α≠π/2 + kπ,k∈Z.

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Lesben Ja eto ponjal i zadanie icpravil.

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