Упростить и найти значение
8a³+12a²b+6ab²+b³ при а=3,5;b=-5
27c³-54c²b+36cd²-8d³ при c=1¹₃;d=0,5
(a+3d)(a²-3ab+9b²) при a=2;b=₋²₃
(4c-3d)(16c²+12cd+9d²) при c=-0,25;d=2,15
8a³+12a²b+6ab²+b³ при а=3,5;b=-5
27c³-54c²b+36cd²-8d³ при c=1¹₃;d=0,5
(a+3d)(a²-3ab+9b²) при a=2;b=₋²₃
(4c-3d)(16c²+12cd+9d²) при c=-0,25;d=2,15
Answers & Comments
8a³ + 12a²b + 6ab² + b³ =
(2a + b)³ =
(2 * 3.5 - 5)³ =
(7 - 5)³ =
2³ = 8
27c³ - 54c²b + 36cd² - 8d³ при c=1¹₃;d=0,5
27c³ - 54c²b + 36cd² - 8d³ =
(3c - 2d)³ =
(3 * 1
(4 - 1)³ =
3³ = 27
(a + 3d)(a² - 3ab + 9b²) при a=2;b=₋²₃
(a + 3d)(a² - 3ab + 9b²) =
(a + 3d)³ =
(2 + 3 * (-
(2 - 2)³ =
0³ = 0
(4c - 3d)(16c² + 12cd + 9d²) при c=-0,25;d=2,15
(4c - 3d)(16c² + 12cd + 9d²) =
(4c - 3d)³ =
(4 * (-0.25) - 3 * 2.15)³ =
(-1 - 6,45)³ =
-7.45³ = -413,493625