1) (х-2а)²+3х²= х²–4ах + 4а² + 3х²= 4х²–4ах + 4а².
2) (4+у)²-у(8+у)= 16 + 8у + у²–8у–у²= 16.
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
1) (х-2а)²+3х²= х²–4ах + 4а² + 3х²= 4х²–4ах + 4а².
2) (4+у)²-у(8+у)= 16 + 8у + у²–8у–у²= 16.