1) =sin(α/2)*ctg(α/4)-cos(α/2)=sin(α/2)*((1+cos(α/2)/sin(α/2))-cos(α/2)=
1+cos(α/2)-cos(α/2)=1
2)=-cos(α/2)*(sin(α/2)/(1-cos(α/2))-sin(α/2)=(-sin(α/2)*cos(α/2)-sin(α/2)+sin(α/2)*cos(α/2))/(cos(1-α/2))=sin(α/2)/(cos(α/2)-1)
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Answers & Comments
1) =sin(α/2)*ctg(α/4)-cos(α/2)=sin(α/2)*((1+cos(α/2)/sin(α/2))-cos(α/2)=
1+cos(α/2)-cos(α/2)=1
2)=-cos(α/2)*(sin(α/2)/(1-cos(α/2))-sin(α/2)=(-sin(α/2)*cos(α/2)-sin(α/2)+sin(α/2)*cos(α/2))/(cos(1-α/2))=sin(α/2)/(cos(α/2)-1)