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3cos a - 3cos(360°- a) + sin (90°- a)+sin(a+90°);
tg(180+a)+tg(270-a);
3cos a - 3cos(360°- a) + sin (90°- a)+sin(a+90°);
tg(180+a)+tg(270-a);
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Решение:
а) 3cos(α) - 3cos(360°-α) + sin(90°-α) + sin(α+90°) = 3cos(α) - 3cos(α) + cos(α) + cos(α) = cos(α) + cos(α) = 2cos(α)
б) tg(180°+α) + tg(270°-α) = tg(α) + ctg(α) = tg(α) + 1/tg(α) = (tg²(α)+1)/tg(α)
Ответ: а) 2cos(α) ; б) (tg²(α)+1)/tg(α)