Упростите: А) (х + 4) ( х - 5) + 20; В) (3х - 4у) (3х + 4у); С) 4b (b - 2) - (b - 5)². Created by DianaFedylova. algebra-ru

Упростите: А) (х + 4) ( х - 5) + 20; В) (3х - 4у) (3х + 4у); С) 4b (b - 2)

Сюръекция А) (х + 4) ( х - 5) + 20 = x^2+4x-5x-20+20=x^2-x
В) (3х - 4у) (3х + 4у) = 9x^2-16y^2
С) 4b (b - 2) - (b - 5)² = 4b^2-8b-(b^2-10b+25) = 4b^2-8b-b^2+10b-25 = 3b^2 +2b-25

3 votes Thanks 6

MizoriesKun А) (х + 4) ( х - 5) + 20=х²+4х-5х-20+20=х²-х = х*(х-1)

В) (3х - 4у) (3х + 4у)= (3х)²-(4у)²=9х²-16у²

С) 4b (b - 2) - (b - 5)²=4b²-8b-b²+10b-25=3b²+2b-25

2 votes Thanks 2

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