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dahsa06
@dahsa06
July 2022
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Упростите и найдите значение алгебраической дроби
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Победитель17
2)((3c-2d)(3c+2d))/(6cd(3c-2d))=(3c+2d)/
(6cd)=(3×(5/3)+2×(1/2))/(6×(5/3)×(1/2))= (5+1)/5=6/5
3)(6x(x+2y))/(5y×(x+2y))=6x/5y=(6×(2/3))/5×(-2/5)= 4/-2=-2
4)(x+3y)^2/(4x(x+3y))=(x+3y)/4x= ((-2/10)+3(-6/10))/4(-2/10)=5/2
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Answers & Comments
(6cd)=(3×(5/3)+2×(1/2))/(6×(5/3)×(1/2))= (5+1)/5=6/5
3)(6x(x+2y))/(5y×(x+2y))=6x/5y=(6×(2/3))/5×(-2/5)= 4/-2=-2
4)(x+3y)^2/(4x(x+3y))=(x+3y)/4x= ((-2/10)+3(-6/10))/4(-2/10)=5/2