Ответ:
В решении.
Объяснение:
Упростить:
1)(х-5)²-7=
=х²-10х+25-7=
=х²-10х+18;
2)6у+(у-3)²=
=6у+у²-6у+9=
=у²+9;
3)(4a-5b)²-16a(a-3b)=
=16a²-40ab+25b²-16a²+48ab=
=25b²+8ab=
=b(25b+8a);
4)x(х-2)-(х-3)²=
=х(х-2)-(х²-6х+9)=
=х²-2х-х²+6х-9=
=4х-9;
5)(8p-q)²-(4p-q)(16p+3q)=
=(64p²-16pq+q²)-(64p²+12pq-16pq-3q²)
=(64p²-16pq+q²)-(64p²-4pq-3q²)=
=64p²-16pq+q² - 64p²+4pq+3q²=
=4q²-12pq=
=4q(q-3p).
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Answers & Comments
Ответ:
В решении.
Объяснение:
Упростить:
1)(х-5)²-7=
=х²-10х+25-7=
=х²-10х+18;
2)6у+(у-3)²=
=6у+у²-6у+9=
=у²+9;
3)(4a-5b)²-16a(a-3b)=
=16a²-40ab+25b²-16a²+48ab=
=25b²+8ab=
=b(25b+8a);
4)x(х-2)-(х-3)²=
=х(х-2)-(х²-6х+9)=
=х²-2х-х²+6х-9=
=4х-9;
5)(8p-q)²-(4p-q)(16p+3q)=
=(64p²-16pq+q²)-(64p²+12pq-16pq-3q²)
=(64p²-16pq+q²)-(64p²-4pq-3q²)=
=64p²-16pq+q² - 64p²+4pq+3q²=
=4q²-12pq=
=4q(q-3p).