упростите выражение:
а) (3у ² - 3у + 1) - (4у - 2)=
б)4b ³ ( 3b ² +b)
Ответ:
а) (3·y² - 3·y + 1) - (4·y - 2) = 3·y² - 3·y + 1 - 4·y + 2 = 3·y² - 7·y + 3;
б) 4·b³·(3·b² + b) = 4·b³·3·b² + 4·b³·b = 12·b³⁺² + 4·b³⁺¹ = 12·b⁵ + 4·b⁴.
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Ответ:
а) (3·y² - 3·y + 1) - (4·y - 2) = 3·y² - 3·y + 1 - 4·y + 2 = 3·y² - 7·y + 3;
б) 4·b³·(3·b² + b) = 4·b³·3·b² + 4·b³·b = 12·b³⁺² + 4·b³⁺¹ = 12·b⁵ + 4·b⁴.