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@Олячкаfff
March 2022
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Упростите выражение:
а) (3у2 – 3у + 1) – (4у – 2); б) 4b3(3b2 + b).
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sergeygutsko
Verified answer
А) (3у² – 3у + 1) – (4у – 2) = 3у² – 3у + 1 – 4у + 2 = 3у² – 7y + 3.
б) 4b³(3b²+b) = 12b⁵ + 4b⁴ = 4b
⁴(3b + 1).
Ответ: а)
3у² – 7y + 3; б) 12b⁵ + 4b⁴ = 4b⁴(3b + 1).
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Verified answer
А) (3у² – 3у + 1) – (4у – 2) = 3у² – 3у + 1 – 4у + 2 = 3у² – 7y + 3.б) 4b³(3b²+b) = 12b⁵ + 4b⁴ = 4b⁴(3b + 1).
Ответ: а) 3у² – 7y + 3; б) 12b⁵ + 4b⁴ = 4b⁴(3b + 1).