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Icetea
@Icetea
June 2021
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Упростите выражение:
б) sin (α + β) - sin β cos α
в) cos 2α + 2 sin^2 α
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mukus13
Verified answer
Sin(a+β)-sin βcosa=sinacos β+sin βcosa-sin βcosa=sina•cos β
cos2a+2sin²a=cos²a-sin²a+2sin²a=cos²a+sin²a=1
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Answers & Comments
Verified answer
Sin(a+β)-sin βcosa=sinacos β+sin βcosa-sin βcosa=sina•cos βcos2a+2sin²a=cos²a-sin²a+2sin²a=cos²a+sin²a=1