упростите выражение cos 2α sin (α-β)

manyny06

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Решение смотри на фотографии

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oganesbagoyan

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Упростите выражениеcos 2α sin (α-β) - cos (β-α) sin2α
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cos 2α*sin(α-β) - cos(β-α)*sin2α = sin(-(β -α))*cos2α* - cos (β-α)* sin2α=-(sin(β -α)*cos2α +- cos (β-α)*sin2α) = -sin(β-α+2α)= -sin(α+β).

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