x*(x^2-1)-(x-2)(x+2)=x(x^2-1)-(x^2-4)
x(x - 1)(x + 1) – (x – 2)(x² + 2x + 4) =
= x·(x²-1) - (x – 2)(x+2)² =
= x³ - x - (x²-4)(x+2) =
= x³ - x - (x³-4x+2x²-8) =
= x³ - x - x³ + 4x - 2x² + 8 =
= - 2x² + 3x + 8
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Answers & Comments
x*(x^2-1)-(x-2)(x+2)=x(x^2-1)-(x^2-4)
x(x - 1)(x + 1) – (x – 2)(x² + 2x + 4) =
= x·(x²-1) - (x – 2)(x+2)² =
= x³ - x - (x²-4)(x+2) =
= x³ - x - (x³-4x+2x²-8) =
= x³ - x - x³ + 4x - 2x² + 8 =
= - 2x² + 3x + 8