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mmalhanova
@mmalhanova
August 2022
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Упростите выражения:
1) 3а(а+2)-(а-3)² =
2) (а-с)(а+с)-с(3а-с)=
3)(в-4)(в+2)-(в-1)²=
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irreversibility
Verified answer
3а(а+2)-(а-3)²=3a²+6a-(a²-6a+9)=3a²+6a-a²+6a-9=2a²+12a-9
(а-с)(а+с)-с(3а-с)=a²-c²-3ac+c²=a²-3ac
(в-4)(в+2)-(в-1)²=в
²+2в-4в-8-(в²-2в+1)=в²+2в-4в-8-в²+2в-1=0-9=-9
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Answers & Comments
Verified answer
3а(а+2)-(а-3)²=3a²+6a-(a²-6a+9)=3a²+6a-a²+6a-9=2a²+12a-9(а-с)(а+с)-с(3а-с)=a²-c²-3ac+c²=a²-3ac
(в-4)(в+2)-(в-1)²=в²+2в-4в-8-(в²-2в+1)=в²+2в-4в-8-в²+2в-1=0-9=-9