a)
(1/(1+ctg²α) + cos²α)* tg²α = tg²α/(1/sin²α) + sin²α = tg²α*sin²α + sin²α = sin²α(tg²α+1) =sin²α(1/cos²α) = tg2α
б)
(tg²α/(1+tg²α) + cos²α)* cos²α = (tg²α/(1/cos²α) + cos²α)* cos²α = (sin²α + cos²α)* cos²α = cos²α
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Answers & Comments
a)
(1/(1+ctg²α) + cos²α)* tg²α = tg²α/(1/sin²α) + sin²α = tg²α*sin²α + sin²α = sin²α(tg²α+1) =sin²α(1/cos²α) = tg2α
б)
(tg²α/(1+tg²α) + cos²α)* cos²α = (tg²α/(1/cos²α) + cos²α)* cos²α = (sin²α + cos²α)* cos²α = cos²α