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amissA
@amissA
July 2022
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katekatysha
(у-4)/(3у-3) : у+1/3 + 2/(y-1)(y+1)= у-4+3/3у-3 : y+1/3 + 2/(y-1)(y+1)= 3(y-1)/3(y-1)(y+1)+2/(y-1)(y+1)= 1/y+1 + 2/(y-1)(y+1)= y-1+2/ (y-1)(y+1)= у+1/(у+1)(у-1)=1/у-1
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