Уравнение реакций в полном и сокращенном виде Ca (OH)2+HNO3--> ZnCl2+KOH--&gt...

June 2022 1 1 Report

Уравнение реакций в полном и сокращенном виде
Ca (OH)2+HNO3-->
ZnCl2+KOH-->
Na2CO3+HCl-->
LiON+H2SO4-->
HClO4+Ca(OH)2-->
NaHCO3+CH3COOH-->
Na3PO4+Ba(NO3)2-->

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DKmag Обозначения: sv - стрелка вниз, su - стрелка вверх
$Ca(OH)_{2}+2HNO_{3}=Ca(NO_{3})_{2}+2H_{2}O$
$Ca^{2+}+2OH^{-}+2H^{+}+2NO_{3}^{-}=Ca^{2+}+2NO_{3}^{-}+H_{2}O$
$2OH^{-}+2H^{+}=2H_{2}O$

$ZnCl_{2}+2KOH=2KCl+Zn(OH)_{2}sv$
$Zn^{2+}+2Cl^{-}+2K^{+}+2OH^{-}=2K^{+}+2Cl^{-}+Zn(OH)_{2}sv$
$Zn^{2+}+2OH^{-}=Zn(OH)_{2}sv$

$Na_{2}CO_{3}+2HCl=H_{2}O+CO_{2}su+2NaCl$
$2Na^{+}+CO_{3}^{2-}+2H^{+}+2Cl^{-}=H_{2}O+CO_{2}+2Na^{+}+2Cl^{-}$
$CO_{3}^{2-}+2H^{+}=H_{2}O+CO_{2}su$

$2LiOH+H_{2}SO_{4}=Li_{2}SO_{4}+2H_{2}O$
$2Li^{+}+2OH^{-}+2H^{+}+SO_{4}^{-}=2Li^{+}+SO_{4}^{-}+2H_{2}O$
$2OH^{-}+2H^{+}=2H_{2}O$

$2HClO_{4}+Ca(OH)_{2}=Ca(ClO_{4})_{2}+2H_{2}O$
$2H^{+}+2ClO_{4}^{-}+Ca^{2+}+2OH^{-}=Ca^{2+}+2ClO_{4}^{-}+H_{2}O$
$2H^{+}+2OH^{-}=2H_{2}O$

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