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BrightOne
@BrightOne
November 2021
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Уравнение с факториалами, подробно
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oganesbagoyan
Verified answer
Task/24101432
---.---.---.---.---
11*C 2x
x =6*C 2
x +1 x+1 ;
11*(2x)! / x!* (2x -x)! =6*(2x+1)!/ (x+1)!*(2x+1 - x -1)! ;
11*(2x)! / x!*
x!
=6*(2x+1)!/ (x+1)!*
x!
;
11*(2x)! / x! =6*(2x+1)!/ (x+1)! ;
11*
(1*2*3*...x)
*(x+1)(x+2)...(x+x) /
x!
=
6*
(1*2*3*...(x+1)
* (x+2)(x+3) ...(2x+1) /
(x+1)!
;
11*
x!
*(x+1)(x+2)...(x+x) /
x!
=6*
(x+1)!
*(x+2)(x+3) ...2x(2x+1) /
(x+1)! ;
11
(x+1)
(x+2)...(x+x)
=6
(x+2)(x+3) ...2x
(
2x+1) ;
11(x+1) =6(2x+1) ;
11x+11 =12x +6 ;
x = 5.
ответ : 5
1 votes
Thanks 1
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Verified answer
Task/24101432---.---.---.---.---
11*C 2x x =6*C 2x +1 x+1 ;
11*(2x)! / x!* (2x -x)! =6*(2x+1)!/ (x+1)!*(2x+1 - x -1)! ;
11*(2x)! / x!* x! =6*(2x+1)!/ (x+1)!*x! ;
11*(2x)! / x! =6*(2x+1)!/ (x+1)! ;
11*(1*2*3*...x) *(x+1)(x+2)...(x+x) / x! =
6*(1*2*3*...(x+1)* (x+2)(x+3) ...(2x+1) / (x+1)! ;
11*x!*(x+1)(x+2)...(x+x) / x! =6*(x+1)!*(x+2)(x+3) ...2x(2x+1) / (x+1)! ;
11(x+1)(x+2)...(x+x)=6(x+2)(x+3) ...2x(2x+1) ;
11(x+1) =6(2x+1) ;
11x+11 =12x +6 ;
x = 5.
ответ : 5