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Appolinariya24
@Appolinariya24
August 2022
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УРАВНЕНИЕ, СРОЧНО!
16-(6-11x)^2=0
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FickenLuder
16-(6-11x)^2=0
16-(36-132x+121x^2)=0
16-36+132x-121x^2=0
-121x^2+132x-20=0
11x^2-12x+20/11=0
D=b^2-4ac
D=(-12)^2-4×11×20/11=144-80=64> 0 - 2 корня.
x1=(-b+корень из D)/2a
x1=(12+8)/2×11=20/22=10/11
x2=(-b-корень из D)/2a
x2=(12-8)/2×11=4/22=2/11
Ответ: 10/11; 2/11.
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Answers & Comments
16-(36-132x+121x^2)=0
16-36+132x-121x^2=0
-121x^2+132x-20=0
11x^2-12x+20/11=0
D=b^2-4ac
D=(-12)^2-4×11×20/11=144-80=64> 0 - 2 корня.
x1=(-b+корень из D)/2a
x1=(12+8)/2×11=20/22=10/11
x2=(-b-корень из D)/2a
x2=(12-8)/2×11=4/22=2/11
Ответ: 10/11; 2/11.