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qwetrdevfyt
@qwetrdevfyt
August 2022
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Уравнение x^2+px+q=0. Имеет корни -5;7 найти q
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repost456
Х²+рх+q=0
по т. Виета х₁+х₂=-р -5+7=2 р=-2
х₁*х₂=q q=-5*7=-35
x²-2x-35=0
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по т. Виета х₁+х₂=-р -5+7=2 р=-2
х₁*х₂=q q=-5*7=-35
x²-2x-35=0