Уравнять методом конкурирующих реакций
1)Cr2(SO4)3+H2O2+NaOH=>Na2SO4+NaCrO4+H2O
2)KI+KMnO4+H2SO4=>I2+MnSO4+K2SO4+H2O
3)KI+KMnO4+NaOH=>K2MnO4+Na2MnO4+I2+KOH
1)Cr2(SO4)3+H2O2+NaOH=>Na2SO4+NaCrO4+H2O
2)KI+KMnO4+H2SO4=>I2+MnSO4+K2SO4+H2O
3)KI+KMnO4+NaOH=>K2MnO4+Na2MnO4+I2+KOH
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Answers & Comments
2)10KI+2KMnO4+8H2SO4= 5I2+2MnSO4+6K2SO4+8H2O
3) 8KMnO4 + KI+8KOH = 8 K2MnO4 + KIO4 + 4 H2O