№3
5√1/5 = √1
2√7 = √28
9√2 = √162;
№4
a) 3-b² / √3+b = (√3-b)(√3+b)/√3+b = √3-b
b) 5-√5 / √2-√10 = √5(√5-1) / √2(1-√5) = - √5 / √2
#5
(4√5+3√3)*√5+√60 = 20 + 3√15 + 2√15 = 20+5√15
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Answers & Comments
№3
5√1/5 = √1
2√7 = √28
9√2 = √162;
№4
a) 3-b² / √3+b = (√3-b)(√3+b)/√3+b = √3-b
b) 5-√5 / √2-√10 = √5(√5-1) / √2(1-√5) = - √5 / √2
#5
(4√5+3√3)*√5+√60 = 20 + 3√15 + 2√15 = 20+5√15