Ответ:
(х-у)(х+у)=х²-y²
(2-x)(x+2)=4-x²
(2х+1)(1-2х)=1-4х²
(2х-у)(2х+у)=4х²-у²
(2х+3у)(3у-2х)=9у²-4х²
(х²-2)(2+х²)=х^4 -4
(3х²-0,2у²)(0.2у+3х²)=9х^4.-0.04
всі крім ост.)
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
(х-у)(х+у)=х²-y²
(2-x)(x+2)=4-x²
(2х+1)(1-2х)=1-4х²
(2х-у)(2х+у)=4х²-у²
(2х+3у)(3у-2х)=9у²-4х²
(х²-2)(2+х²)=х^4 -4
(3х²-0,2у²)(0.2у+3х²)=9х^4.-0.04
всі крім ост.)