Ответ:
Объяснение:
Mr(Al2O3) = 27*2 + 16*3 =102
W(Al) = Ar(Al) *n / Mr(Al2O3) *100% = 27*2 / 102 *100% =53
W(O) = Ar(O) *n / Mr(Al2O3) *100% = 16*3 / 102 *100% = 47%
W (Al) = 52,9%
W (O) = 47,1%
M (Al2O3) = 27 × 2 + 16 × 3 = 102 г/моль
102 г/моль — 100%
54 г/моль — X
X = 54 × 100 / 102 = 52,9% — W (Al)
W (O) = 100 – 52,9 = 47,1%
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Ответ:
Объяснение:
Mr(Al2O3) = 27*2 + 16*3 =102
W(Al) = Ar(Al) *n / Mr(Al2O3) *100% = 27*2 / 102 *100% =53
W(O) = Ar(O) *n / Mr(Al2O3) *100% = 16*3 / 102 *100% = 47%
Ответ:
W (Al) = 52,9%
W (O) = 47,1%
Объяснение:
M (Al2O3) = 27 × 2 + 16 × 3 = 102 г/моль
102 г/моль — 100%
54 г/моль — X
X = 54 × 100 / 102 = 52,9% — W (Al)
W (O) = 100 – 52,9 = 47,1%