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skurikhinanata
@skurikhinanata
December 2021
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В 100 г воды растворено 15 г хлорида натрия.Чему равна процентная концентрация раствора?
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mrvladimir2
Verified answer
Дано:
m(H2O) = 100 r
m(NaCl) - 15 r
Найти:
ω(NaCl)=?
m(p-pa NaCl) = 100 r+15 r = 115 r
ω(NaCl) = m(NaCl)*100%/m(p-paNaCl) = 15г*100%/115 г =13,04%
Ответ: 13,04%
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skurikhinanata
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Answers & Comments
Verified answer
Дано:m(H2O) = 100 r
m(NaCl) - 15 r
Найти:
ω(NaCl)=?
m(p-pa NaCl) = 100 r+15 r = 115 r
ω(NaCl) = m(NaCl)*100%/m(p-paNaCl) = 15г*100%/115 г =13,04%
Ответ: 13,04%