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dij2
@dij2
August 2022
1
15
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В 200 г воды при 20'С помещают 300 г железа при 10'С и 400 г меди при 25'С.Найти получившуюся температуру (если можно с дано и системой си)
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Artem112
Verified answer
1 железо
2 вода
3 медь
c1m1(t-t1)+с2m2(t-t2)=c3m3(t3-t)
450*0.3(t-10)+4200*0.2(t-20)=380*0.4(25-t)
135(t-10)+840(t-20)=152(25-t)
135t-1350+840t-16800=3800-152t
1127t=21950
t=19.5 (С)
Ответ: 19,5 С
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Answers & Comments
Verified answer
1 железо2 вода
3 медь
c1m1(t-t1)+с2m2(t-t2)=c3m3(t3-t)
450*0.3(t-10)+4200*0.2(t-20)=380*0.4(25-t)
135(t-10)+840(t-20)=152(25-t)
135t-1350+840t-16800=3800-152t
1127t=21950
t=19.5 (С)
Ответ: 19,5 С