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Maria4833902
@Maria4833902
June 2022
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В арифметической прогрессии а1=-3 и d=5. Найдите разность s15-s14
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dibilkill
A15=a1+d*14=-3+5*14=70-3=67
a14=a15-a=67-5=62
s15=((a1+a15)/2)*15=((-3+67)/2)*15=(64/2)*15=32*15=480
s14=((a1+a14)/2)*14=((=3+62)/2)*14)=(59/2)*14=59*7=413
s15-s14=480-413=67
7 votes
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dibilkill
во второй строке опечатка a14=a15-d=67-5=62
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Answers & Comments
a14=a15-a=67-5=62
s15=((a1+a15)/2)*15=((-3+67)/2)*15=(64/2)*15=32*15=480
s14=((a1+a14)/2)*14=((=3+62)/2)*14)=(59/2)*14=59*7=413
s15-s14=480-413=67