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school4444
@school4444
July 2022
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в арифметической прогрессии а7=2 и а10=7 найти а19
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Djasurxon
An=a1+d(n-1)
a10=a7+3d
7=2+3d
5=3d
d=5/3
a7=a1+6d
2=a1+6*5/3
2=a1+10
a1=-8
a19=a10+9d=7+9*5/3=7+15=22
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tamarabernukho
A₇=a₁+6d=2
a₁₀=a₁+9d=7
3d=5 d=5/3
a₁=2-10=-8
a₁₉=-8+5/3*18=-8+15=7
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Answers & Comments
a10=a7+3d
7=2+3d
5=3d
d=5/3
a7=a1+6d
2=a1+6*5/3
2=a1+10
a1=-8
a19=a10+9d=7+9*5/3=7+15=22
a₁₀=a₁+9d=7
3d=5 d=5/3
a₁=2-10=-8
a₁₉=-8+5/3*18=-8+15=7