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ZalinaQ
@ZalinaQ
July 2022
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в арифметическрй прогрессии a13=17 и a17=11.Найдите a21
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sedinalana
Verified answer
A13=a1+12d=17⇒a1=17-12d
a17=a1+16d=11⇒a1=11-16d
17-12d=11-16d
-12d+16d=11-17
4d=-6
d=-1,5
a1=17-12*(-1,5)=17+18=35
a21=a1+20d=35+20*(-1,5)=20-30=-10
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Verified answer
A13=a1+12d=17⇒a1=17-12da17=a1+16d=11⇒a1=11-16d
17-12d=11-16d
-12d+16d=11-17
4d=-6
d=-1,5
a1=17-12*(-1,5)=17+18=35
a21=a1+20d=35+20*(-1,5)=20-30=-10