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alla510
@alla510
August 2022
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В Δ-ке ABC ∠A=70° и ∠С=60°. Биссектриса BD делит Δ-к ABC на два Δ-ка - ABD и BCD. Найдите углы этих треугольников.
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анонимка2001
∠АBD=1/2(180-(∠BAC+∠BCA))= 25 =∠BDC
∠BDA=180-70-25=85
∠BDC=180-60-25=95
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Answers & Comments
∠BDA=180-70-25=85
∠BDC=180-60-25=95