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Kainer
@Kainer
July 2022
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В электроприборе за 40 мин электрический ток 5 А выполнил работу 180 кДж. Определите сопротивление прибора.
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milana2057
Q=R*I^*T
R=Q/I^*T
R=180000Дж/25*240=30 Ом
4 votes
Thanks 5
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R=Q/I^*T
R=180000Дж/25*240=30 Ом