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Princesska906
@Princesska906
August 2022
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В геометрической прогрессии b1+b5=17 и b2+b6=34. Найти b3.
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Valfeta
(b2+b6)-(b1+b5)=34-17
(b2+b6)-(b1+b5)=17
b2=17
b=17:2
b=8,5
b3=8,5*3
b3=25,5
Как то так
2 votes
Thanks 5
Vas61
B₅=b₁q⁴ b₂=b₁q b₆=b₁q⁵
b₁+b₁q⁴=17 b₁q+b₁q⁵=34
b₁(1+q⁴)=17 b₁q(1+q⁴)=34
1+q⁴=17/b₁ b₁q·17/b₁=34
17q=34
q=2
b₁+b₁·2⁴=17
b₁+16b₁=17
b₁=1
b₃=b₁q² b₃=1·2²=4
4 votes
Thanks 6
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Answers & Comments
(b2+b6)-(b1+b5)=17
b2=17
b=17:2
b=8,5
b3=8,5*3
b3=25,5
Как то так
b₁+b₁q⁴=17 b₁q+b₁q⁵=34
b₁(1+q⁴)=17 b₁q(1+q⁴)=34
1+q⁴=17/b₁ b₁q·17/b₁=34
17q=34
q=2
b₁+b₁·2⁴=17
b₁+16b₁=17
b₁=1
b₃=b₁q² b₃=1·2²=4