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DeltaplanX
@DeltaplanX
July 2022
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В геометрической прогрессии b2=6 b3=12. Найти сумму первых 6 членов прогрессии.
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НикаВодолей
Q=b3/b2=12/6=2
b1=b2/q=6/2=3
S6=(b1(1-q^5))/(1-q)=(3*(1-32)/(1-2)=3*31=93
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Answers & Comments
b1=b2/q=6/2=3
S6=(b1(1-q^5))/(1-q)=(3*(1-32)/(1-2)=3*31=93