Ответ:
x1 = -5; x2 = 3
Объяснение:
-x^2 - 2x + 15 ≤ 0
D = (-2)^2 - 4 × (-1) × 15 = 64
x1,2 = 2 ± √64/ -1 × 2 = -5; 3
Ответ: x1 = -5; x2 = 3
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Ответ:
x1 = -5; x2 = 3
Объяснение:
-x^2 - 2x + 15 ≤ 0
D = (-2)^2 - 4 × (-1) × 15 = 64
x1,2 = 2 ± √64/ -1 × 2 = -5; 3
Ответ: x1 = -5; x2 = 3