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Likesuomi
@Likesuomi
June 2022
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В каком объёме 5 М раствора сожержится 50 г нитрата калия?
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hidrógeno
M = n/V ==》V=n÷M
n = m/Mr
Mr (KNO3)=39,1+14+16×3=101,1g/mol
n = 50 g ÷ 101,1g/mol=0,495mol
V=0,495mol÷5M=0,099 L
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Answers & Comments
n = m/Mr
Mr (KNO3)=39,1+14+16×3=101,1g/mol
n = 50 g ÷ 101,1g/mol=0,495mol
V=0,495mol÷5M=0,099 L