Home
О нас
Products
Services
Регистрация
Войти
Поиск
Наташа45
@Наташа45
August 2021
0
7
Report
В каком случае преобразование выполнено верно? 1). (4-b)*(b+4)=b^2-16 2). -(b-1)*(3-4b)=(1-b)*(4b-3) 3). (b+1)*(3-2b)=3+b-2b^2 4). (b-4)^2=b^2-4a+16
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
×
Report "В каком случае преобразование выполнено верно? 1). (4-b)*(b+4)=b^2-16 2). -(b-1..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.