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Колючая
@Колючая
May 2021
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В каком случае преобразование выполнено верно? 1.) (4-b)(b+4)=b^2-16 2.) (b+1)(3-2b)=3+b-2b^2 3.) -(b-1)(3-4b)=(1-b)(4b-3) 4.) (b-4)^2= b^2-4a+16
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