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nastya30112011
@nastya30112011
August 2022
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Тело движется вдоль оси x по уравнению x=2+4t^2+6t^3 здесь t- в с, x- в м, определите ускорение в метрах /а/ в момент времени t=3,2 c?
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creepsmart
V=x'=8t+18t*t
a=x''=8+36t
a(3,2)=8+36*3.2
2 votes
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Answers & Comments
a=x''=8+36t
a(3,2)=8+36*3.2