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Makskoldj
@Makskoldj
July 2022
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В параллелограмме ABCD высота BH=8,AH=6,HD=10.Найдите косинус угла BAH
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25890
По т. Пифагора
AH^2+BH^2=AB^2
36+64=AB^2
AB^2=100
AB=10
cosA=AH/AB
cosA=6/10
cosA=0,6
Ответ: 0,6
3 votes
Thanks 2
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Answers & Comments
AH^2+BH^2=AB^2
36+64=AB^2
AB^2=100
AB=10
cosA=AH/AB
cosA=6/10
cosA=0,6
Ответ: 0,6