Ответ:

program sumr;

procedure summa;

var i, factorial, sum:integer;

begin

factorial:=1;

sum:=0;

for i:=1 to 6 do

begin

factorial:=factorial*i;

sum:=sum+factorial;

end;

writeln ('summa ryada = ', sum);

end;

begin

summa;

end.

Объяснение: