Home
О нас
Products
Services
Регистрация
Войти
Поиск
timakovar
@timakovar
August 2022
1
4
Report
в первом букву (а) и во втором тоже букву (а)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sangers1959
Verified answer
√(x²-4x)/(x²+4x-32)
x²-4x≥0 x*(x-4)≥0 -∞___+___0___-___4___+___+∞ x∈(-∞;0]U(4;+∞)
x²+4x-32≠0 x²+8x-4x-32≠0 x*(x+8)-4*(x+8)≠0 (x+8)*(x-4)≠0 x₁≠-8 x₂≠4
Ответ: (-∞;-8)U(-8;0]U(4;+∞).
2x⁴-4x³=0
2x³*(x-2)|=0 |÷2
x³*(x-2)=0
x³=0
x₁=0
x-2=0
x₂=2
Ответ: x₁=0 x₂=2.
1 votes
Thanks 1
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "в первом букву (а) и во втором тоже букву (а)..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
√(x²-4x)/(x²+4x-32)x²-4x≥0 x*(x-4)≥0 -∞___+___0___-___4___+___+∞ x∈(-∞;0]U(4;+∞)
x²+4x-32≠0 x²+8x-4x-32≠0 x*(x+8)-4*(x+8)≠0 (x+8)*(x-4)≠0 x₁≠-8 x₂≠4
Ответ: (-∞;-8)U(-8;0]U(4;+∞).
2x⁴-4x³=0
2x³*(x-2)|=0 |÷2
x³*(x-2)=0
x³=0
x₁=0
x-2=0
x₂=2
Ответ: x₁=0 x₂=2.