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AlVincent
@AlVincent
August 2021
1
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В первом задание надо еще сделать ионное уравнение.
2 не нужно
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cherevaty
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А)![Pb(OH)_2+2HNO_3=Pb(NO_3)_2+2H_2O\\Pb(OH)_2+2H^++2NO_3=Pb^{2+}+2NO_3^{2-}+H_2O\\Pb(OH)_2+2H^+=Pb^{2+}+H_2O Pb(OH)_2+2HNO_3=Pb(NO_3)_2+2H_2O\\Pb(OH)_2+2H^++2NO_3=Pb^{2+}+2NO_3^{2-}+H_2O\\Pb(OH)_2+2H^+=Pb^{2+}+H_2O](https://tex.z-dn.net/?f=Pb%28OH%29_2%2B2HNO_3%3DPb%28NO_3%29_2%2B2H_2O%5C%5CPb%28OH%29_2%2B2H%5E%2B%2B2NO_3%3DPb%5E%7B2%2B%7D%2B2NO_3%5E%7B2-%7D%2BH_2O%5C%5CPb%28OH%29_2%2B2H%5E%2B%3DPb%5E%7B2%2B%7D%2BH_2O)
Б)![H_3PO_4+3KOH=K_3PO_4+3H_2O\\3H^++PO_4^{3-}+3K^++3OH^-=3K^++PO_4^{3-}+3H_2O\\3OH^-+3H^+=3H_2O H_3PO_4+3KOH=K_3PO_4+3H_2O\\3H^++PO_4^{3-}+3K^++3OH^-=3K^++PO_4^{3-}+3H_2O\\3OH^-+3H^+=3H_2O](https://tex.z-dn.net/?f=H_3PO_4%2B3KOH%3DK_3PO_4%2B3H_2O%5C%5C3H%5E%2B%2BPO_4%5E%7B3-%7D%2B3K%5E%2B%2B3OH%5E-%3D3K%5E%2B%2BPO_4%5E%7B3-%7D%2B3H_2O%5C%5C3OH%5E-%2B3H%5E%2B%3D3H_2O)