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zaichikov
@zaichikov
July 2022
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В правильной четырёхугольной пирамиде высота 4 м, боковое ребро 5 м. Найти объём.
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sedinalana
Verified answer
SABCD,h=SO=4м,SA=SB=SC=SD=5м,AB=BC=CD=AD
AO=√(SA²-SO²)=√(25-16)=3м
AC=2AO=6м
AC=AB√2
AB=6/√2=3√2м
V=1/3*AB²*S0=1/3*18*4=24м³
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Answers & Comments
Verified answer
SABCD,h=SO=4м,SA=SB=SC=SD=5м,AB=BC=CD=ADAO=√(SA²-SO²)=√(25-16)=3м
AC=2AO=6м
AC=AB√2
AB=6/√2=3√2м
V=1/3*AB²*S0=1/3*18*4=24м³