2sin^2x+√2*(sinx*cos45+cos*sin45)=cosx
2sin^2x+√2*√2/2(sinx+cosx)=cosx
2sin^2x+sinx+cosx-cosx=0
2sin^2x+sinx=sinx(2sinx+1)=0
a)sinx=0; x1=pik
b)sinx=-1/2; x2=-pi/6+2pin и x3=-5pi/6+2pin
n,m-целые
интервалу [-2pi;-pi/2] принадлежат
x=-{-2pi; -pi;-5pi/6}
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Answers & Comments
2sin^2x+√2*(sinx*cos45+cos*sin45)=cosx
2sin^2x+√2*√2/2(sinx+cosx)=cosx
2sin^2x+sinx+cosx-cosx=0
2sin^2x+sinx=sinx(2sinx+1)=0
a)sinx=0; x1=pik
b)sinx=-1/2; x2=-pi/6+2pin и x3=-5pi/6+2pin
n,m-целые
интервалу [-2pi;-pi/2] принадлежат
x=-{-2pi; -pi;-5pi/6}