October 2021 0 11 Report
В прямоугольном параллелепипеде ABCDA1B1C1D1 ребро ВС=4, ребро АВ=2√5, ребро ВВ1=4. Точка К-середина ребра СС1. Найдите площадь сечения В1, А1и К
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