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August 2022
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В раствор пропанола массой 90 г с массовой долей спирта 10% поместили натрий массой 3,25 г. Рассчитайте объем выделившегося водорода.
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alima1958
Verified answer
90г 3,25г хл
2C2H5OH +2Na =2C2H5ONa +H2 V(H2)= 3.25г*22.4л/46г=1.58л
92г 46г 22,4л
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Verified answer
90г 3,25г хл2C2H5OH +2Na =2C2H5ONa +H2 V(H2)= 3.25г*22.4л/46г=1.58л
92г 46г 22,4л